a)\(ƯCLN\left(6,12,24\right)\)
Ta có
\(6=2.3\)
\(12=3.2^2\)
\(24=3.2^3\)
\(\RightarrowƯCLN\left(6,12,24\right)=2.3=6\)
b)\(ƯCLN\left(256,48\right)\)
Ta có
\(256=2^8\)
\(48=2^4.3\)
\(\RightarrowƯCLN\left(256,48\right)=2^4=16\)
c)\(ƯCLN\left(15,45,105\right)\)
Ta có
\(15=3.5\)
\(45=3^2.5\)
\(105=3.5.7\)
\(\RightarrowƯCLN\left(15,45,105\right)=3.5=15\)
a, ƯCLN (6;12;24)
6= 2.3
12= 22.3
24= 3.23
\(\Rightarrow\)ƯCLN (6;12;24)= 2.3= 6
b, ƯCLN(256; 48)
256= 28
48= 24.33
\(\Rightarrow\)ƯCLN (256; 48)= 24= 16
c, ƯCLN (15; 45; 105)
15= 3.5
45= 32.5
105= 3.5.7
\(\Rightarrow\)ƯCLN (15; 45; 105)= 3.5= 15
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