\(\frac{x}{6}=\frac{2}{y}=\frac{1}{2}\)
Ta có: \(\frac{x}{6}=\frac{1}{2}\) => \(x=\frac{1}{2}.6\)
=> \(x=3\)
\(\frac{2}{y}=\frac{1}{2}\) => \(y=2:\frac{1}{2}\)
=> \(y=4\)
Vậy ...
#)Giải :
Ta có : \(\frac{x}{6}=\frac{2}{y}\Rightarrow xy=6.2=12\)
\(\Rightarrow\left(x,y\right)\in\left\{\left(2,6\right);\left(3;4\right)\left(1;12\right)\right\}\)
Nhưng vì điều kiện cho bằng \(\frac{1}{2}\)
\(\Rightarrow\left(x,y\right)\in\left\{3,4\right\}\)
\(\Rightarrow x=3;y=4\)
\(\frac{x}{6}=\frac{2}{y}=\frac{1}{2}\)
Ta có : \(\frac{x}{6}=\frac{1}{2}\)
=>\(x.2=6.1\)
\(x.2=6\)
\(x=3\)
Ta có :\(\frac{2}{y}=\frac{1}{2}\)
\(2.2=y.1\)
\(4=y.1\)
\(=>y.1=4\)
\(y=4\)
hc tốt