Question

Tìm a;b;c biết a-1/5=b-2/3=c-2/2 và a+2b-c=6
 

Answer 1

Áp dụng t/c dtsbn:

\(\dfrac{a-1}{5}=\dfrac{b-2}{3}=\dfrac{c-2}{2}=\dfrac{2b-4}{6}=\dfrac{a-1+2b-4-c+2}{5+6-2}=\dfrac{6}{9}=\dfrac{2}{3}\)

\(\Rightarrow\left\{{}\begin{matrix}a-1=\dfrac{2}{3}.5=\dfrac{10}{3}\\b-2=\dfrac{2}{3}.3=2\\c-2=\dfrac{2}{3}.2=\dfrac{4}{3}\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}a=\dfrac{13}{3}\\b=4\\c=\dfrac{10}{3}\end{matrix}\right.\)