a/ \(\Leftrightarrow\left[{}\begin{matrix}a>1\\\frac{a+1}{2}< -1\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}a>1\\a< -3\end{matrix}\right.\)
b/ \(\left(-\infty;5\right)\cup\left(-3;+\infty\right)=R\) nên với mọi a thì \(\left[a;\frac{a+1}{2}\right]\in\left(-\infty;5\right)\cup\left(-3;+\infty\right)\)