Question

tim a biet:(a+1)+(a+2)+(a+3)+(a+4)+(a+5)=315

Answer 1

(a+1)+(a+2)+(a+3)+(a+4)+(a+5)=315

<=> (a+a+a+a+a)+(1+2+3+4+5)=315

<=> 5a+15=315

<=> 5a=300

<=> a=60

Answer 2

(a + 1) + ( a+ 2) + (a + 3 ) + (a + 4 ) + ( a + 5 ) = 315

(a + a + a + a + a) + (1 + 2 + 3 + 4 + 5 ) = 315

a * 5 + 15 = 315

a * 5 = 315 - 15

a * 5 = 300

a = 300 : 5

a = 60

k cho mk nha

Answer 3

5a+15=315

5a=315-15

5a=300

=> a=60

Answer 4

\(\left(a+1\right)+\left(a+2\right)+\left(a+3\right)+\left(a+4\right)+\left(a+5\right)=315\)

\(\Leftrightarrow\left(a+a+a+a+a\right)+\left(1+2+3+4+5\right)=315\)

\(\Leftrightarrow5a+15=315\)

\(\Leftrightarrow5a=300\)

\(\Leftrightarrow a=60\)

Vậy\(a=60\)

Answer 5

<=> 5a+(1+2+3+4+5)=315

<=>5a+15=315

<=>5a=300

<=>a=60

vậy .......

Answer 6

(a+1)+(a+2)+(a+3)+(a+4)+(a+5)=315

=(a+a+a+a+a)+(1+2+3+4+5)=315

=5a+15=315

=>5a=300

=>a=300:5=60

vậy a=60

Answer 7

cảm mơn :333