Có : \(\frac{a}{4}=\frac{b}{7}\Rightarrow\frac{a}{12}=\frac{b}{21}\)(1)
\(5b=3c\Rightarrow\frac{b}{3}=\frac{c}{5}\Rightarrow\frac{b}{21}=\frac{c}{35}\) (2)
Từ (1) và (2)
\(\Rightarrow\frac{a}{12}=\frac{b}{21}=\frac{c}{35}=\frac{2a}{24}=\frac{2a-b+c}{24-21+35}=\frac{114}{38}=3\)
\(\Rightarrow\hept{\begin{cases}a=3.12=36\\b=3.21=63\\c=3.35=105\end{cases}}\)