Ta có: \(2^m-2^n=2^8\)
\(2^n\left(2^{m-n}-1\right)=2^8\)
\(2^{m-n}-1=1\)
\(2^1-1=1\)
\(m-n=1\)
\(2^8\left(2^{9-8}-1\right)=2^8\)
\(\Rightarrow\)\(m=9\)
\(n=8\)
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