\(m_{P_2O_5}=500\cdot42.6\%=213\left(kg\right)\)
\(n_{P_2O_5}=\dfrac{213}{142}=1.5\left(kmol\right)\)
\(n_{H_2SO_4}=1.5\cdot3=4.5\left(kmol\right)\)
\(m_{dd_{H_2SO_4}}=\dfrac{4.5\cdot98}{70\%}=630\left(kg\right)\)
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