Đặt A=\(\frac{16.17-5}{16.16+11}\)
\(\Rightarrow A=\frac{16.\left(16+1\right)-5}{16.16+11}\)
\(\Rightarrow A=\frac{16.16+16-5}{16.16+11}\)
\(\Rightarrow A=\frac{16.16+11}{16.16+11}\)
=> A=1
\(\frac{16.17-5}{16.16+11}=\frac{16.\left(16+1\right)-5}{16.16+11}=\frac{16.16+16-5}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)
\(\frac{16.17-5}{16.16+11}\)= \(\frac{272-5}{256+11}\)=\(\frac{267}{267}\)= 1