a) 2(x-1)2 - 4(x+3)2 + 2x(x-5)
= 2(x2 -2x +1)- 4(x2 + 6x +9) + 2x2 -10x
= 2x2 - 4x + 2 -4x2 - 24x - 36 + 2x2 - 10x
= (2x2 + 2x2 - 4x2) - (4x + 24x+10x) +(2-36)
= -38x-34
b) 2(2x+5)2 -3(4x+1)(1-4x)
= 2(4x2 + 20x + 25) + 3(4x+1)(4x-1)
= 8x2 +40x + 50 + 3(16x2 -1)
= 8x2 + 40x + 50 + 48x2 - 3
=56x2 +40x + 47
a, \(2\left(x-1\right)^2-4\left(x+3\right)^2+2x\left(x-5\right)\)
\(=2\left(x^2-2x+1\right)-4\left(x^2+6x+9\right)+2x\left(x-5\right)\)
\(=2x^2-4x+2-4x^2-24x-36+2x^2-10=-28x-44\)
b, \(2\left(2x+5\right)^2-3\left(4x+1\right)\left(1-4x\right)\)
\(=2\left(4x^2+20x+25\right)-3\left(1-16x^2\right)\)
\(=8x^2+40x+50-3+48x^2=56x^2+40x+47\)
mình sửa dòng cuối phần a nhé
\(=2x^2-4x+2-4x^2-24x-36+2x^2-10x=-38x-34\)
2.(x-1)^2 - 4.(3+x)^2 + 2x.(x-5)
= 2.( x^2 - 2x + 1 ) - 4.( 9 + 6x + x^2 ) + 2x^2 - 10x
= 2x^2 - 4x + 2 - 36 - 24x - 4x^2 + 2x^2 - 10x
= - 38x - 34
2.(2x+5)^2 - 3.(4x+1).(1-4x)
= 2.(4x^2+20x+25) - 3.(1-16x^2)
= 8x^2 + 40x + 50 - 3 + 48x^2
= 56x^2 + 40x + 47