Ta có:
45 = 5.9
\(\Rightarrow\overline{24x68y}⋮\left\{5;9\right\}\)
\(\Rightarrow\overline{24x68y}⋮5\Leftrightarrow y\in\left\{0;5\right\}\)
Mà\(\overline{24x68y}⋮9\Leftrightarrow y=0;x=7\)
\(\Rightarrow247680⋮45\)
Vậy x;y lần lượt là: 7;0
\(A⋮45\Rightarrow A⋮5\); \(A⋮9\)
Vì \(A⋮5\) nên \(y=0\text{ hoặc }y=5\)
- Nếu y = 0 thì \(\overline{24x680}⋮9\)\(\Rightarrow2+4+x+6+8+0⋮9\Rightarrow18+\left(x+2\right)⋮9\)
\(\Rightarrow x+2⋮9\) mà \(2\le x+2\le11\),\(\Rightarrow x+2=9\Rightarrow x=7\)
Nếu y = 5 thì \(\overline{24x685}⋮9\Rightarrow2+4+x+6+8+0⋮9\Rightarrow18+\left(x+7\right)=9\)
\(\Rightarrow x+7⋮9\) mà \(7\le x+7\le16\)\(\Rightarrow x+7=9\Rightarrow x=2\)
Vậy \(y=0\text{ hoặc }5\) ; \(x=7\text{ hoặc }2\)