Question

\(\text{(2x^3-5x^2 +6x-15):(2x-5)}\)

Answer 1

\(\dfrac{\left(2x^3-5x^2+6x-15\right)}{\left(2x-5\right)}\)

\(=\dfrac{\left(2x-5\right)\cdot\left(x^2+3\right)}{\left(2x-5\right)}\)

\(=x^2+3\)