Câu đầu ko dịch được đề, lỗi kí tự rồi bạn
b/
\(\Leftrightarrow2cos^6x+sin^4x+2cos^2x-1=0\)
\(\Leftrightarrow2cos^2x\left(cos^4x+1\right)+\left(sin^2x-1\right)\left(sin^2x+1\right)=0\)
\(\Leftrightarrow cos^2x\left(2cos^4x+2\right)-cos^2x\left(sin^2x+1\right)=0\)
\(\Leftrightarrow cos^2x\left(2cos^4x+1-sin^2x=0\right)\)
\(\Leftrightarrow cos^2x\left(2cos^4x+cos^2x\right)=0\)
\(\Leftrightarrow cos^4x\left(2cos^2x+1\right)=0\)
\(\Leftrightarrow cos^4x=0\Leftrightarrow cosx=0\)
\(\Leftrightarrow x=\frac{\pi}{2}+k\pi\)