Để\(\frac{n}{n+3}\)
la stn =>n chia het cho n+3
Ta có: n=n+3-3
Mà n chia hết cho n+3=>[(n+3)-3]chia hết cho n+3
n+3 chia hết cho n+3=>3 chia hết cho n+3
=>n+3 thuoc Ư(3)
mà Ư(3)={1;3;-1;-3}
| n+3 | 1 | 3 | -1 | -3 |
| n | -2 | 0 | -4 | -6 |
mà n la stn =>n=0
Vậy n=0
tim cac so nguyen n de\(\frac{3n-1}{n-1}\) co gia tri la so nguyen
c1: Tap hop cac gia tri nguyen cua x thoa man \(\left(x+\frac{5}{4}\right)\left(x-\frac{19}{7}\right)\)<0
c2: Neu x,y la cac so nguyen thoa man 2xy+4y=6 thi y co the nhan nhung gia tri nam trong tap hop nao
c3: tim 3 so x,y,z biet x+y=8,x+z=10,y+z=12
C4: Gia tri cua x thoa man (x+3)^2=25 va x^3>0 la x=
Tap hop cac gia tri nguyen de A = 3x+5/2+x dat gia tri nguyen la x = ..............
tap hop cac gia tri nguyen cua x thoa man (x^2+4x+13) chia het cho x+4 co so phan tu la
tim so nguyen n de phan so sau co gia tri la so nguyen
A=\(\frac{6n+5}{2n-1}\)
TAP HOP CAC SO TU NHIEN N DE A=8N+193/4N+3 LA SO TU NHIEN S={.......}NHAP GIA TRI THEO THU TU TANG DAN
NHANH LEN CAC BAN OI
Cho Bt : n-3/n-5
a,Tinh gia tri cua A biet n = 6
b,So nguyen n phai co dieu kien gi de A la phan so ?
c, Tim n de A nhan gia tri nguyen
tim cac so nguyen n de phan so sau co gia tri nguyen
2n+3 / 7
TIm x thuoc Z de cac ps sau co gia tri la so nguyen :
D = \(\frac{2x-3}{x-1}\)