Để (x-2)*(2x+14)=0 thì x-2=0 hoặc 2x+14=0
Nếu x-2=0
=>x=2
Nếu 2x+14=0
=>2x=-14
=>x=-7
Vậy tập hợp các giá trị đó là:{-7,2}
Ta có: ( x - 2 ) . ( 2x + 14 ) = 0
\(\Rightarrow\)x - 2 = 0 và 2x + 14 = 0
Ta có TH1:
x - 2 = 0 \(\Rightarrow\)x = 2
TH2:
2x + 14 = 0 \(\Rightarrow\)2x = 14 \(\Rightarrow\)x =- 7
Vậy x = {2;-7}
Mình sừa lại chỗ TH2:
2x + 14 = 0 \(\Rightarrow\)2x = -14 \(\Rightarrow\)x = -7
(x-2)(2x+14)=0
<=>2(x-2)(x+7)=0
<=>\(\orbr{\begin{cases}x-2=0\\x+7=0\end{cases}}\)
<=>\(\orbr{\begin{cases}x=2\\x=-7\end{cases}}\)
Vậy tập hợp các giá trị của x thỏa mãn (x-2)(2x+14)=0
là S={-7;2}
Vì (x-2).(2x+14)=0 nên x-2=0 hay 2x+14=0
Nếu x-2=0 Thì
x=0+2=2
Nếu 2x+14=0 thì
2x=0+14=14
x=14:2
x=7
Vậy \(x\in\left(2;7\right)\)
Mình làm nhầm : Sửa lại:
Vì (x-2).(2x+14)=0 nên x-2=0 hoặc 2x+14=0
Nếu x-2=0\(\Rightarrow\)x=2+0=2
Nếu 2x+14=0\(\Rightarrow\)2x=0-14=-14
x=-14:2=-7
Vậy \(x\in\left(-7;2\right)\)
Để (x-2)*(2x+14)=0 thì x-2=0 hoặc 2x+14=0
Nếu x - 2 = 0 => x = 2
Nếu 2x + 14 = 0 => 2x = -14
=>x = -7
Vậy tập hợp các giá trị đó là: { -7,2 }
7,2 nhé 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%
\(x=\orbr{\begin{cases}2\\-7\end{cases}}\)