Question

\(\sqrt{\dfrac{-1}{2x}}.\sqrt{-8x^5}\) với x<0

Answer 1

`\sqrt((-1)/(2x)) .\sqrt(-8x^5)`

`=\sqrt( (-1)/(2x) . (-8x^5))`

`=\sqrt( 8x^5)/(2x))`

`=\sqrt(4x^2)`

`=|2x|=-2x`