Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
\(\sqrt{21-6\sqrt{6}}\)
\(=\sqrt{3\left(7-2\sqrt{6}\right)}\)
\(=\sqrt{3\left(6-2\sqrt{6}+1\right)}\)
\(=\sqrt{3\left(\sqrt{6}-1\right)^2}\)
\(=\sqrt{3}\left(\sqrt{6}-1\right)\)
\(=\sqrt{3}.\sqrt{6}-\sqrt{3}.1\)
\(=9\sqrt{2}-\sqrt{3}\)
Tinh gia tri bieu thuc \(\sqrt{\frac{5+2\sqrt{6}}{5-\sqrt{6}}+\sqrt{\frac{5-2\sqrt{6}}{5+\sqrt{6}}}}\)
Tinh gia tri bieu thuc \(\sqrt{\frac{5+2\sqrt{6}}{5-\sqrt{6}}}+\sqrt{\frac{5-2\sqrt{6}}{5+\sqrt{6}}}\)
\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-6\sqrt{20}}}}\)
So cuoi la 20 nhe
Tinh gia tri bieu thuc
\(2\sqrt{3+\sqrt{5-\sqrt{13+\sqrt{48}}}}\)
tinh gia tri bieu thuc
\(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
Tinh gia tri bieu thuc
Tinh Gia tri bieu thuc \(\frac{1}{\sqrt{7-\sqrt{24}}+1}-\frac{1}{\sqrt{7+\sqrt{24}+1}}\)
Tinh gia tri bieu thuc \(\frac{1}{\sqrt{7}-\sqrt{24}+1}-\frac{1}{\sqrt{7}+\sqrt{24}+1}\)
Tinh gia tri bieu thuc
\(\left(\sqrt{\frac{25}{16}-\sqrt{\frac{9}{16}}}\right):5\)
\(\left(\frac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}+\frac{5-\sqrt{5}}{1-\sqrt{5}}\right):\frac{1}{\sqrt{7}-\sqrt{5}}\)
Tinh gia tri bieu thuc