so sánh:
A=\(\frac{2017^{2018}+1}{2017^{2019}+1}\);B=\(\frac{2017^{2017}+1}{2017^{2018}+1}\)
So sánh: \(\frac{2017}{2018+2019}\)+ \(\frac{2018}{2017+2019}\)+ \(\frac{2019}{2017+2018}\)và 1
Bạn nào làm đúng mình tik cho
So sánh
A=\(\frac{2017^{2017}+1}{2017^{2018}+1}\)
\(B=\frac{2017^{2018}+1}{2017^{2019}+1}\)
so sánh A=\(\frac{2016^{2017}+1}{2017^{2018}+1}\)và B=\(\frac{2017^{2018}+1}{2017^{2017}+1}\)
so sánh A và B
A = \(\frac{2015}{2016}-\frac{2016}{2017}+\frac{2017}{2018}-\frac{2018}{2019}\)
B=\(\frac{-1}{2015.2016}-\frac{1}{2017.2018}\)
Cho
A = \(\frac{2017^{2018}+1}{2017^{2018}-3}\)
B= \(\frac{2017^{2018}-1}{2017^{2018}-5}\)
So sánh A và B
sa sánh C= 2018^2011+1/ 2018^2019 +1 và D= 2018^2017 /2018^2013 +1
So sánh \(\frac{2017}{2018}+\frac{2018}{2019}và\frac{2015}{2016}+\frac{2016}{2017}\)
So sánh 2 biểu thức:
M = \(\frac{2016}{2017}\)+\(\frac{2017}{2018}\)+\(\frac{2018}{2019}\)
N = \(\frac{2016+2017+2018}{2017+2018+2019}\)
