Question

So sánh:

A=10^2019+7 / 10^2019+1

B=10^2020+9 / 10^2020+3

Giúp mk với các bn ơi

Answer 1

A= (10^2019+7)/(10^2019 + 1) = 1+ (6 / 10 ^2019+1)

B = ( 10 ^ 2020 +9) / ( 10 ^2020 +3) = 1 +( 6 / 10^ 2020 +3)

A -B = (6 / 10 ^2019+1) - (6 / 10^2020 +3) >0

=> A > B

Answer 2

thanks bạn nha