9920=(992)10=980110.Do 9801 < 9999 nên 9920<999910
535=31257;221=87. Do 3125>8 nên suy ra 221<535
a)221=(23)7=87
535=(55)7=31257
có 8<3125 suy ra 221<31257
Ta có:\(2^{21}=\left(2^3\right)^7=8^7\)
\(5^{35}=\left(5^5\right)^7=25^7\)
\(25^7>8^7=>2^{21}< 5^{35}\)
b,\(99^{20}=\left(99^2\right)^{10}=9801^{10}\)
=>\(9801^{10}< 9999^{10}=>99^{20}< 9999^{10}\)
a,Vì 5^35 > 4^35 = 2^70 >2^21 nên 5^35 > 2^21
b,Vì 9999^10 > 9801^10=99^20 nên 9999^10 >99^20
Ta có: 221=(23)7=87
535=(55)7=31257
=> 87<31257
=> 221<535
a, Ta có:
\(2^{21}=\left(2^3\right)^7=8^7\)
\(5^{35}=\left(5^5\right)^7=3125^7\)
Vì 8<3125\(\Rightarrow\)\(8^7< 3125^7\)
\(\Rightarrow2^{21}< 5^{35}\)
Vậy \(2^{21}< 5^{35}\)
b, Ta có \(99^{20}=\left(99^2\right)^{10}=9801^{10}\)
Vì 9801<9999
\(\Rightarrow\)\(9801^{10}< 9999^{10}\)
\(\Rightarrow99^2< 9999^{10}\)
Vậy\(99^{20}< 9999^{10}\)
a)2^21= (2^3)^7 = 8^7
5^35 =(5^5)^7 = 3125^7
Vì 3125^7> 8^7 nên 2^21<5^35
b) 99^20 và 9999^10
99^20=(99^2)^10= 198^10
Vì 198^10< 9999^10 nên 99^20< 9999^10
Bài làm:
a) \(2^{21}=\left(2^3\right)^7=8^7< 3125^7=\left(5^5\right)^7=5^{35}\)
\(\Rightarrow2^{21}< 5^{35}\)
b) \(99^{20}=\left(99^2\right)^{10}=9801^{10}< 9999^{10}\)
\(\Rightarrow99^{20}< 9999^{10}\)
Học tốt!!!!