so sánh \(\left(\frac{-1}{5}\right)^{255}và\left(\frac{-1}{2}\right)^{579}\)
So sánh: \(\left(-\frac{1}{5}\right)^{255}\) và \(\left(-\frac{1}{2}\right)^{579}\)
So sánh:
\(\left(-\frac{1}{5}\right)^{255}\) và \(\left(-\frac{1}{2}\right)^{579}\)
TÍnh:
\(\hept{\begin{cases}\\\end{cases}18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0,38\right)}]:(19-2\frac{2}{3}.4\frac{3}{4})\)
So sánh:
\(5^{255}\)và \(2^{579}\)
So sánh các số sau:
a) \(0,5\sqrt{100}-\sqrt{\frac{4}{25}}v\text{à}\left(\sqrt{1\frac{1}{9}}-\sqrt{\frac{9}{16}}\right):5\)
b) \(\sqrt{25+9}v\text{à}\sqrt{25}+\sqrt{9}\)
a.\(3\left(x-1\right)=3\left(y-2\right);4\left(y-2\right)=3\left(z-3\right)v\text{à}2x+3y-z=-250\)
b.\(\frac{x^3}{8}=\frac{y^3}{64}=\frac{z^3}{216}v\text{à}x^2+y^2+z^2=14\)
giải ra giúp mik nha!!!!!!!!!
\(A=\left(\frac{-2}{5}x^2y\right)\left(\frac{15}{8}xy^2\right)\left(-x^3y^2\right)\)
\(Cho\frac{x}{3}=\frac{y}{2}v\text{à }x+3y=3\)
TÍNH A?
So sánh :
\(a,2^{30}v\text{à}3^{20}\)
\(b,5^{300}v\text{à}3^{500}\)
\(c,2^{24}v\text{à}3^{16}\)
\(d,\left(0,3\right)^{40}v\text{à}\left(0,1\right)^{20}\)
Cho x = 3,7.So sánh :
\(A=\left[x\right]+\left[x+\frac{1}{5}\right]+\left[x+\frac{2}{5}\right]+\left[x+\frac{3}{5}\right]+\left[x+\frac{4}{5}\right]\)
và B = [5x]
