so sánh \(\left(\frac{-1}{5}\right)^{255}và\left(\frac{-1}{2}\right)^{579}\)
So sánh:
\(\left(-\frac{1}{5}\right)^{255}v\text{à}\left(-\frac{1}{2}\right)^{579}\)
So sánh:
\(\left(-\frac{1}{5}\right)^{255}\) và \(\left(-\frac{1}{2}\right)^{579}\)
TÍnh:
\(\hept{\begin{cases}\\\end{cases}18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0,38\right)}]:(19-2\frac{2}{3}.4\frac{3}{4})\)
So sánh:
\(5^{255}\)và \(2^{579}\)
Cho x = 3,7.So sánh :
\(A=\left[x\right]+\left[x+\frac{1}{5}\right]+\left[x+\frac{2}{5}\right]+\left[x+\frac{3}{5}\right]+\left[x+\frac{4}{5}\right]\)
và B = [5x]
So sánh : \(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{1000^2}-1\right)Và\frac{-1}{2}\)
cho \(A=\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{2016^2}-1\right)\left(\frac{1}{2017^2}-1\right)\)và b=-1/2
Hãy so sánh A với B
Cho A= \(\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{2013^2}-1\right)\left(\frac{1}{2014^2}-1\right)\) và B=\(\frac{-1}{2}\). Hãy so sánh A và B
so sánh A và \(\frac{-1}{2}\)có A=\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right).....\left(\frac{1}{100^2}-1\right)\)
