thấy B/A
lớn hơn 1 .Vây B
lớn hơn A
\(A=\frac{10^9+5}{10^9-2}\)
\(=\frac{10^9-2}{10^9-2}+\frac{7}{10^9-2}\)
\(=1+\frac{7}{10^9-2}\)
\(B=\frac{10^9}{10^9-7}\)
\(=\frac{10^9-7}{10^9-7}+\frac{7}{10^9-7}\)
\(=1+\frac{7}{10^9-7}\)
Vì \(7\over10^9-5\)<\(7\over10^9-7\) nên A<B