So sánh A=\(\frac{101+100}{101-100}\)và B=\(\frac{101^2+100^2}{101^2-100^2}\)
So sánh A = 1 + 1/(√2) + 1/(√3) + ... + 1/(√100) và B = 2√(101) - 1
\(A=1+\frac{3}{2^3}+\frac{4}{2^4}+...+\frac{100}{2^{100}}\)
\(\frac{A}{2}=\frac{1}{2}+\frac{3}{2^4}+\frac{4}{2^5}+....+\frac{100}{2^{101}}\)\(A-\frac{A}{2}=\left(1+\frac{3}{2^3}+....+\frac{100}{2^{100}}\right)-\left(\frac{1}{2}+\frac{3}{2^4}+.....+\frac{100}{2^{101}}\right)\)
\(\frac{A}{2}=\frac{1}{2}+\frac{3}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+....+\frac{1}{2^{100}}-\frac{100}{2^{101}}\)
\(\frac{A}{2}=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+....+\frac{1}{2^{100}}-\frac{1}{2^{101}}\)
\(\frac{A}{2}=\left(1-\left(\frac{1}{2}\right)^{101}\right).2-\frac{100}{2^{101}}\)
\(\frac{A}{2}=\frac{2^{101}-1}{2^{100}}-\frac{100}{2^{101}}\)
\(A=\frac{2^{101}-1}{2^{99}}-\frac{100}{2^{100}}\)
tính tổng
S=1/2*3 - 2/3*4 +...+ 99/100*101 - 100/101*102
Cho A=2^99+1/2^100+1
B=2^100+1/2^101+1
so sánh a và b
Tính
\(\frac{1}{2+\sqrt{2}}+\frac{1}{3\sqrt{2}+2\sqrt{3}}+...+\frac{1}{101\sqrt{100}+100\sqrt{101}}\)
cho các số thực dương thỏa mãn \(a^{100}+b^{100}=a^{101}+b^{101}=a^{102}+b^{102},tính\) \(A=a^{2015}+b^{2015}\)
1-1+2-2+..+100-100+101=?
Buồn quá ai kb với mk ko
Tính:
( 100 + 99/2 + 98/3 +.....+ 1/100 ) : ( 1/2 + 1/3 +........+ 1/101 ) - 2 = ?
