A = 1/1.2.3 + 1/2.3.4 + 1/3.4.5 + ... + 1/2014.2015.2016
=> A = 1/2.(2/1.2.3 + 2/2.3.4 + 2/3.4.5 + ... + 2/2014.2015.2016)
=> A = 1/2.(1/1.2 - 1/2.3 + 1/2.3 - 1/3.4 + 1/3.4 - 1/4.5 + ... + 1/2014.2015 - 1/2015.2016)
=> A = 1/2.(1/2 - 1/2015.2016)
=> A < 1/2.1/2 = 1/4
Ta có: \(A=\frac{1}{1.2.3}+\frac{1}{2.3.4}+....+\frac{1}{2014.2015.2016}\)
\(\Rightarrow2A=\frac{2}{1.2.3}+\frac{2}{2.3.4}+....+\frac{2}{2014.2015.2016}\)
\(\Rightarrow2A=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+....+\frac{1}{2014.2015}-\frac{1}{2015.2016}\)
\(\Rightarrow2A=\frac{1}{1.2}-\frac{1}{2015.2016}\)
\(\Rightarrow A=\left(\frac{1}{2}-\frac{1}{2015.2016}\right):2\)
\(\Rightarrow A=\frac{1}{4}-\frac{1}{2015.2016.2}\)
\(\Rightarrow A< \frac{1}{4}\)
Ta có:
A = \(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{2014.2015.2016}\)
2A = \(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{2014.2015.2016}\)
2A = \(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{2014.2015}-\frac{1}{2015.2016}\)
2A = \(\frac{1}{1.2}-\frac{1}{2015.2016}\)
=> 2A < \(\frac{1}{1.2}=\frac{1}{2}\)
=> A < \(\frac{1}{4}\)
Vậy A < \(\frac{1}{4}\)