Question

So sanh :

A = \(\frac{2000}{2001}\) +  \(\frac{2001}{2002}\)

B = \(\frac{2000+2001}{2001+2002}\)

 

Answer 1

Ta có: 2000/2001>1/2 ;  2001/2002>1/2

=>A=1/2+1/2=1=>A>1

B=2000+2001/2001+2002=4001/4003<1

A>1;B<1

=>A>B

Vậy A>B

Answer 2

Theo mình nghĩ là :

B = \(\frac{2000}{2001+2002}\)+ \(\frac{2001}{2001+2002}\)

Mà \(\frac{2000}{2001+2002}=\frac{2000}{4003}\)< \(\frac{2000}{2001}\)

\(\frac{2001}{2001+2002}\)= \(\frac{2001}{4003}\)<  \(\frac{2001}{2002}\)

Nên  : A > B

Không chắc nữa !!!