\(27^{11}=\left(3^3\right)^{11}=3^{33};81^8=\left(3^4\right)^8=3^{32}\)
Vì \(33>32\Rightarrow27^{11}>81^8\)
Vậy 2711>818
Ta có: \(27^{11}=\left(3^3\right)^{11}=3^{33}\)
\(81^8=\left(3^4\right)^8=3^{32}\)
Vì \(3^{33}>3^{32}\) nên \(27^{11}>81^8\)
phân tích 2711=333 ( 2711=(33)11 )
818=332 ( 818=(34)8 )
Vì 333<332 nên 2711<818
Ta có :
\(27^{11}=\left(3^3\right)^3=3^9\)
\(81^8=\left(3^4\right)^8=3^{32}\)
Vì : \(9< 32\)nên \(27^{11}< 81^8\)
\(27^{11}=\left(3^3\right)^{11}=3^{33}\)
\(81^8=\left(3^4\right)^8=3^{32}\)
vi \(3^{33}>3^{32}\) nen \(2^{11}>81^8\)
vay \(2^{11}>81^8\)