\(\frac{a}{3}=\frac{2a+2}{5}\)
\(\Rightarrow5a=3.\left(2a+2\right)\)
\(\Rightarrow5a=6a+6\)
\(\Rightarrow5a-6a=6\)
\(\Rightarrow a=-6\)
\(\frac{a}{3}=\frac{2a+2}{5}\Rightarrow5a=3\left(2a+2\right)\Rightarrow5a=6a+10\Rightarrow a=6\)
sory mk giải nhầm
\(\frac{a}{3}=\frac{2a+2}{5}\Rightarrow\frac{5a}{15}=\frac{6a+6}{15}\Rightarrow5a=6a+6\Rightarrow6=5a-6a\Rightarrow a=-6\)
Vậy a=-6