Question

Sắp xếp theo thứ tự giảm dần:
a) $2 \sqrt{3}, 3 \sqrt{2}, \sqrt{13}, 2 \sqrt{6}$;

b) $\dfrac{1}{2} \sqrt{5}, \dfrac{1}{3} \sqrt{39}, \dfrac{1}{5} \sqrt{35}, \dfrac{1}{4} \sqrt{32}$.

Answer 1

a) 2√6>3√2>√13>2√326

b)1/3√39>1/4√32>1/5√35>1/2√51339

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Answer 2

Bạn Tạ Bảo Trân làm sai

Answer 3

Tạ Bảo Trân sai thì  bn phải sửa chứ

Answer 4

a) \(2\sqrt{3};\sqrt{13};3\sqrt{2};\)\(2\sqrt{6}\)

b)\(\frac{1}{2}\sqrt{5};\frac{1}{5}\sqrt{35};\frac{1}{4}\sqrt{32};\)\(\frac{1}{3}\sqrt{39}\)

mong chú nhận xét bài làm của cháu

Answer 5

a) \(2\sqrt{6},3\sqrt{2},\sqrt{13},2\sqrt{3}\)                                                                                                                    b) 31​39​>41​32​>51​35​>21​5​.        

Answer 6

a, căn 13, 2 căn 3, 3 căn 2 , 2 căn 16

b, 

Answer 7

a) 2√3;√13;3√2;2√6

b) 1/2 √5;1/5 √35; 1/4√32; 1/3 √39

Answer 8

a) 2√3;√13;3√2;2√6

b) 1/2 √5;1/5 √35; 1/4√32; 1/3 √39

Answer 9

a) 2√6>3√2>√13>√3

b) 1/3*√39>1/4*√32>1/5*√35>1/2*√5

Answer 10

a. 

Answer 11

a) 2 can 6, 3 can 2, can 13, 2 can 3

b) 1/3 can 39, 1/4 can 32,1,5 can 35, 1/2 can 5

Answer 12

1/3căn 39>1/4căn 32>1/5căn 35>1/2căn 5

Answer 13

A- 2V6>3V2>V13>2V3

B- 1/3V39>1/4V32>1/5V35>1/2V5

Answer 14

a, \(2\sqrt{6}>3\sqrt{2}>\sqrt{13}>2\sqrt{3}\)

b,

\(\dfrac{1}{2}\sqrt{5}=\sqrt{\dfrac{5}{4}}\)

\(\dfrac{1}{3}\sqrt{39}=\sqrt{\dfrac{13}{3}}\)

\(\dfrac{1}{5}\sqrt{35}=\sqrt{\dfrac{7}{5}}\)

\(\dfrac{1}{4}\sqrt{32}=\sqrt{4}\)

\(\dfrac{1}{3}\sqrt{39}>\dfrac{1}{4}\sqrt{32}>\dfrac{1}{5}\sqrt{35}>\dfrac{1}{2}\sqrt{5}\)

Answer 15

a. \(2\sqrt{6};3\sqrt{2};\sqrt{13};\sqrt{3}\)

b. \(\dfrac{1}{3}\sqrt{39};\dfrac{1}{4}\sqrt{32};\dfrac{1}{5}\sqrt{35};\dfrac{1}{2}\sqrt{5}\)

Answer 16

a, 2√6; 3√2; √13,2; 2√3

b, (1/3)√39;  (1/4)√32; (1/5)√35; (1/2)√5

Answer 17

a)\(2\sqrt{6}\) > \(3\sqrt{2}\) > \(\sqrt{13}\) > 2\(\sqrt{3}\)

b)\(\dfrac{1}{2}\sqrt{5}\) = \(\sqrt{\dfrac{5}{4}}\)

    \(\dfrac{1}{3}\sqrt{39}\) = \(\sqrt{\dfrac{13}{3}}\)

     \(\dfrac{1}{5}\sqrt{35}\) = \(\sqrt{\dfrac{7}{5}}\)

      \(\dfrac{1}{4}\sqrt{32}\) = \(\sqrt{4}\)

\(\dfrac{1}{3}\sqrt{39}\) > \(\dfrac{1}{4}\sqrt{32}\) > \(\dfrac{1}{5}\sqrt{35}\) > \(\dfrac{1}{2}\sqrt{5}\)

Answer 18

a) \(2\sqrt{6}>3\sqrt{2}>\sqrt{13}>2\sqrt{3}\)

b) \(\dfrac{1}{2}\sqrt{5}=\sqrt{\dfrac{5}{4}};\)

     \(\dfrac{1}{3}\sqrt{39}=\sqrt{\dfrac{13}{3}};\)

     \(\dfrac{1}{5}\sqrt{35}=\sqrt{\dfrac{7}{5}}\)

     \(\dfrac{1}{4}\sqrt{32}=\sqrt{4}\)

     \(\dfrac{1}{3}\sqrt{39}>\dfrac{1}{4}\sqrt{32}>\dfrac{1}{5}\sqrt{35}>\dfrac{1}{2}\sqrt{5}\)

Answer 19

a, \(\) \(2\sqrt{6}>3\sqrt{2}>\sqrt{13}>2\sqrt{3}\)

b, \(\dfrac{1}{3}\sqrt{39}>\dfrac{1}{4}\sqrt{32}>\)\(\dfrac{1}{5}\sqrt{35}>\)\(\dfrac{1}{2}\sqrt{5}\)

Answer 20

a) $2\sqrt{3};\sqrt{13};3\sqrt{2};$$2\sqrt{6}$

b)$\frac{1}{2}\sqrt{5};\frac{1}{5}\sqrt{35};\frac{1}{4}\sqrt{32};$$\frac{1}{3}\sqrt{39}$

Answer 21

a, 2căn 6 >3 căn 2> căn 13>2căn 3

b, 1/2căn 5 = căn 5/4

1/3căn 39= căn 13/3

1/5 căn 35= căn 7/5

1/4 căn 32= căn 4

1/3căn 39>1/4 căn 32>1/5 căn 35>1/2 căn 5

Answer 22

a) 2√3, 3√2, √13, 2√6

<=> √12<√13<√18<√24

Vậy 2√3<√13<3√2<2√6

Answer 23

a) 2\(\sqrt{6}\) > 3\(\sqrt{2}\) > \(\sqrt{13}\) > 2\(\sqrt{3}\)

b) \(\dfrac{1}{3}\sqrt{39}\) > \(\dfrac{1}{4}\sqrt{32}\) > \(\dfrac{1}{5}\sqrt{35}\) > \(\dfrac{1}{2}\sqrt{5}\)