a) \(\frac{6^7}{4^3x9^2}\)
b) \(\frac{12^3x15^3}{4^3x25^2x9^2}\)
c) \(\frac{2^{11}+3x2^{10}}{10x4^5}\)
d) \(\frac{9^4x2-3^6}{34x3^7}\)
So sánh hai phân số: \(\frac{-7}{31}va\frac{6}{31}\);\(\frac{-97}{128}va\frac{-99}{128}\) ;\(\frac{3}{7}va\frac{-6}{7}\);\(\frac{2}{5}va\frac{4}{5}\)\(\frac{-2}{5}va\frac{13}{5}\)\(\frac{4}{9}va\frac{7}{9}\)\(\frac{5}{12}va\frac{7}{12}\)\(\frac{-7}{15}va\frac{-8}{15}\)\(\frac{-2}{5}va\frac{4}{5}\)\(\frac{4}{7}va\frac{3}{7}\)\(\frac{-11}{13}va\frac{-15}{13}\)\(\frac{-2}{7}va\frac{-4}{14}\)\(\frac{_{-5}}{7}va\frac{-10}{7}\)\(\frac{-13}{5}va\frac{1}{5}\)\(\frac{-6}{7}va\frac{-3}{7}\)\(\frac{3}{7}va\frac{5}{7}\)\(\frac{-7}{9}va\frac{-5}{9}\)\(\frac{-3}{7}va\frac{-5}{7}\)\(\frac{-13}{9}va\frac{1}{9}\) so sánh số cùng mẫu số \(\frac{-7}{13};\frac{-4}{13}\) \(\frac{1}{7};\frac{-4}{-7}\)
Bài 1: Sắp xếp các phân số sau theo thứ tự:
a) Tăng dần: \(\frac{-5}{6};\frac{7}{8};\frac{7}{24};\frac{16}{17};\frac{-3}{4};\frac{2}{3}\)
b) Giảm dần: \(\frac{-5}{8};\frac{7}{10};\frac{-16}{19};\frac{20}{23};\frac{214}{315};\frac{205}{107}\)
Bài 2: So sánh hai phân số:
a) \(\frac{102}{97}va\frac{99}{101}\)
b)\(\frac{-5}{14}va\frac{-4}{11}\)
Tính nhanh:
A=\(\frac{1}{6x10}+\frac{1}{10x14}+\frac{1}{14x18}+\frac{1}{18x22}+\frac{1}{22x26}+\frac{1}{26x30}\)
B=\(\frac{5}{2x3}+\frac{5}{3x4}+\frac{5}{4x5}+...+\frac{5}{8x9}\)
C=\(\left(\frac{7^2}{2x9}+\frac{7^2}{9x16}+...+\frac{7^2}{65x72}\right):\left(\frac{1}{3}-\frac{7}{36}\right)\)
D=\(\frac{2}{2x3x4}+\frac{2}{3x4x5}+...+\frac{2}{37x38x39}+\frac{2}{38x39x40}\)
E=\(\frac{202202}{1212}+\frac{202202}{2020}+\frac{202202}{3030}+\frac{202202}{4242}+\frac{202202}{5656}\)
Nhanh lên nha!Ngày mai mik đi học rồi!
so sánh các phân số:
a)\(\frac{2}{3}và\frac{1}{4}\)
b)\(\frac{7}{10}va\frac{7}{8}\)
c)\(\frac{6}{7}va\frac{3}{5}\)
d)\(\frac{14}{21}va\frac{60}{72}\)
e)\(\frac{16}{9}va\frac{24}{13}\)
g)\(\frac{27}{82}va\frac{26}{75}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
So sanh A va B, biet :
a)\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};B=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
b)\(A=\frac{7^{10}}{1+7+7^2+...+7^9};B=\frac{5^{10}}{1+5+5^2+...+5^9}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\cdot230\frac{1}{5}+46\frac{3}{4}}{\frac{\left(1\frac{3}{7}+\frac{10}{3}\right)}{\left(12\frac{1}{3}-14\frac{2}{7}\right)}}\)
\(A=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
