Question

rút gọn:

\(\frac{\sqrt{6}+\sqrt{14}}{2\sqrt{3}+\sqrt{28}}\)

Answer 1

\(\frac{\sqrt{6}+\sqrt{14}}{2\sqrt{3}+\sqrt{28}}\) = \(\frac{\sqrt{2}\left(\sqrt{3}+\sqrt{7}\right)}{\sqrt{12}+\sqrt{28}}\)= \(\frac{\sqrt{2}\left(\sqrt{3}+\sqrt{7}\right)}{\sqrt{4}\left(\sqrt{3}+\sqrt{7}\right)}\)= \(\frac{\sqrt{2}}{2}\)