\(\frac{a^3-125}{3a^2+15a+75}\)
\(=\frac{\left(a-5\right)\left(a^2+5a+25\right)}{3\left(a^2+5a+25\right)}\)
\(=\frac{a-5}{3}\)
Ủng hộ nhé~~~~!!! :3
\(\frac{a^3-125}{3a^2+15a+75}=\frac{\left(a-5\right).\left(a^2+5a+25\right)}{3.\left(a^2+5a+25\right)}=\frac{a-5}{3}\\ \)
Ta có :
\(\frac{a^3-125}{3a^2+15a+75}=\frac{a^3-5^3}{3a^2+3.a.5+3.5^2}=\frac{\left(a-5\right).\left(a^2+a.5+5^2\right)}{3.\left(a^2+a.5+5^2\right)}=\frac{a-5}{3}\)
Ủng hộ mik nha !!!