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Các câu hỏi tương tự
rut gon bien thuc ( can 5 - can 7 ) ^2
rut gon mo ngoac don 1 tru can 2 tat ca mu 2
rut gon
can (12-6can3) - can (21-12can3)
rut gon
can 16a^4b^6 / can 128a^6b^6 (a<0, bkhac 0)
Rut gon bieu thuc sau
(15√200 - 3√450 + 2√50) : √10
Minh can sieu nhanh ma phai dung, Thanks truoc nha!!
1) Rut gon bieu thuc A = \(\left(4+\sqrt{7}\right).\left(\sqrt{2}-\sqrt{14}\right).\sqrt{4-\sqrt{7}}\)
1/ Rut gon bieu thuc sau:
a) \(\sqrt{12-2\sqrt{35}}+\sqrt{7-2\sqrt{10}}-\sqrt{\sqrt{49}}\)
b) \(\frac{\sqrt{7}-5}{2}-\frac{6}{\sqrt{7}-2}+\frac{1}{3+\sqrt{7}}+\frac{3}{5+2\sqrt{7}}\)
RUT GON :
\(\left(\sqrt{28}-\sqrt{12}-\sqrt{7}\right)\sqrt{9}+2\sqrt{21}\)
\(\frac{a^5+a^6+a^7+a^8}{a^{-5}+a^{-6}+a^{-7}+a^{-8}}\)
Rut gon bieu thuc tren.