Question

Rút gọn phân thức:

\(\frac{3x^2+6x+12}{x^3-8}\)

                              Giúp mình vs

Answer 1

ĐKXĐ : \(x\ne2\)

\(\frac{3x^2+6x+12}{x^3-8}\)

\(=\frac{3\left(x^2+2x+4\right)}{\left(x-2\right)\left(x^2+2x+4\right)}\)

\(=\frac{3}{x-2}\)

Answer 2

3x²+6x+12/x³-8

=3*(x^2+2x+4)/x^3-2^3

=3*(x^2+2x+4)/(x-2)*(x^2+2x+4)

=3/x-2