Question

rút gọn phân thức

\(\dfrac{x-3}{x}-\dfrac{x}{x-3}-\dfrac{9}{x\left(x-3\right)}\)

Answer 1

\(=\dfrac{x^2-6x+9-x^2-9}{x\left(x-3\right)}=\dfrac{-6x}{x\left(x-3\right)}=\dfrac{6}{3-x}\)