Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
\(S=1+\frac{1}{3}+\frac{1}{3^2}+........+\frac{1}{3^n}\)
\(3S=3+1+\frac{1}{3}+.......+\frac{1}{3^{n-1}}\)
\(\Rightarrow3S-S=\left(3+1+\frac{1}{3}+......+\frac{1}{3^{n-1}}\right)-\left(1+\frac{1}{3}+\frac{1}{3^2}+......+\frac{1}{3^n}\right)\)
\(\Rightarrow2S=3-\frac{1}{3^n}\Rightarrow2S=\frac{3^{n+1}-1}{3^n}\Rightarrow S=\frac{3^{n+1}-1}{2.3^n}\)
Rut gon bieu thuc: S = \(\frac{1}{^{2^1}}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{100}}\)
Rut gon bieu thuc sau
A=\(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{100}}\)
Rut gon bieu thuc : 1 +\(\frac{1}{2}+\frac{1}{2^2}\)+\(\frac{1}{2^3}\)+.......+\(\frac{1}{2^{2012}}\)
cho bieu thuc A =\(\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}\)
a)rut gon bieu thuc
b)chung minh rang neu a la so nguyen thi gia tri cua bieu thuc tim duoc o cau a la mot phan so toi gian
\(A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}\)
a/ Rut gon bieu thuc
b/ Chung minh rang neu a la so nguyen thi gia tri cua bieu thuc tim duoc o cau a, la mot phan so toi gian
\(A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}\)
a)rut gon bieu thuc
b)chung minh rang neu a la so nguyen thi gia tri cua bieu thuc tim duoc cua cau a la mot phan so toi gian
Rut gon:
A=\(\frac{1}{3}+\frac{1}{3^3}+\frac{1}{3^5}+...+\frac{1}{3^{49}}\)
rut gon bieu thuc:(1/2+1)(1/3+1)(1/4+1).....(1/99+1)
Rut gon \(A=\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)....\left(\frac{1}{100^2}-1\right)\)