Question

rút gọn biểu thức A= \(\left(\dfrac{1}{\sqrt{x}}+\dfrac{\sqrt{x}}{\sqrt{x}+1}\right)\):\(\dfrac{\sqrt{x}}{x+\sqrt{x}}\)

Answer 1

Lời giải:
ĐKXĐ: $x>0$

\(A=\frac{\sqrt{x}+1+x}{\sqrt{x}(\sqrt{x}+1)}:\frac{\sqrt{x}}{\sqrt{x}(\sqrt{x}+1)}=\frac{x+\sqrt{x}+1}{\sqrt{x}(\sqrt{x}+1)}.\frac{\sqrt{x}(\sqrt{x}+1)}{\sqrt{x}}=\frac{x+\sqrt{x}+1}{\sqrt{x}}\)