Giải:
a.\(\sqrt{3\text{± }2\sqrt{2}}=\sqrt{2\text{± }2\sqrt{2.1+1}}=\sqrt{\left(2\sqrt{2\text{± }1}\right)^2}=\sqrt{2\text{± }1}\)
b.\(\sqrt{8\text{± }2\sqrt{7}}=\sqrt{7\text{± }2\sqrt{7.1+1}}=\sqrt{\left(\sqrt{7\text{± }1}\right)^2}=\sqrt{7\text{± }1}\)
Mk nghĩ z! Chúc bn hc tốt!