Question

PTĐTTNT: 3x⁵ - 10x⁴ - 8x³ - 3x² +10x + 8

Answer 1

phân tích đa thức thành nhân tử chung ( phương pháp nhóm )

Answer 2

        

       \(3x^5-10x^4-8x^3-3x^2+10x+8\)

\(=3x^5-3x^4-7x^4+7x^3-15x^3+15x^2-18x^2+18x-8x+8\)

\(=\left(x-1\right)\left(3x^4-7x^3-15x^2-18x-8\right)\)

\(=\left(x-1\right)\left[3x^3\left(x-4\right)+5x^2\left(x-4\right)+5x\left(x-4\right)+2\left(x-4\right)\right]\)

\(=\left(x-1\right)\left(x-4\right)\left[3x^3+5x^2+5x+2\right]\)

\(=\left(x-1\right)\left(x-4\right)\left[x^2\left(3x+2\right)+x\left(3x+2\right)+\left(3x+2\right)\right]\)

\(=\left(x-1\right)\left(x-4\right)\left(3x+2\right)\left(x^2+x+1\right)\)