Question

pppppp

Answer 1

\(\frac{x-1}{2016}+\frac{x-2}{2015}+\frac{x-3}{2014}+..+\frac{x-2016}{1}=2016\)

\(\Leftrightarrow\frac{x-1}{2016}-1+\frac{x-2}{2015}-1+\frac{x-3}{2014}-1+...+\frac{x-2016}{1}-1=2016\)

\(\Leftrightarrow\frac{x-2017}{2016}+\frac{x-2017}{2015}+\frac{x-2017}{2014}+...+\frac{x-2017}{1}=0\)

\(\Leftrightarrow x-2017\left(1+\frac{1}{2}+...+\frac{1}{2014}+\frac{1}{2015}+\frac{1}{2016}\right)=0\)

Có: \(1+\frac{1}{2}+...+\frac{1}{2014}+\frac{1}{2015}+\frac{1}{2016}\ne0\)

\(\Rightarrow x-2017=0\)

\(\Rightarrow x=2017\)

Answer 2

x = 2017

Answer 3

nhầm, cái đoạn: \(\Leftrightarrow\frac{x-1}{2016}-1+\frac{x-2}{2015}-1+\frac{x-3}{2014}-1+...+\frac{x-2016}{1}-1=0\) nhé, sửa lại đoạn đó -_-