Question

Phân tích thành nhân tử

a)\(6x^2+23x-18\)

 b)\(x^4+324\)

Answer 1

a)6x²+23x-18

=6x²-4x+27x-18

=2x(3x-2)+9(3x-2)

=(2x+9)(3x-2)

b)x⁴+324

=(x⁴+18²+36x²)-36x²

=(x²+18)²-36x²

 =(x²-6x+18)(x²+6x+18)

Answer 2

a,6x²+23x-18

=6x²+27x-4x-18

=(6x²+27x)-(4x+18)

=3x(2x+9)-2(2x-9)

=(3x-2)(2x+9)

Answer 3

x⁴ + 324

=(x²)² + 18²

=(x²)² + 36x² + 18² - 36x²

⁼(x² + 18)² - 36x²

⁼[(x² + 18) - 6x][(x² + 18) + 6x]

=[x² + 18 - 6x][x² + 18 + 6x]

=(x² - 6x + 18)(x² + 6x + 18)