Question

Phân tích thành nhân tử :

e, 8x\(^3\)y\(^3\) + \(\dfrac{1}{27}\)

f, 125y\(^3\) - x\(^6\)

Answer 1

e) \(8x^3y^3+\dfrac{1}{27}\)

\(=\left(2xy\right)^3+\left(\dfrac{1}{3}\right)^3\)

\(=\left(2xy+\dfrac{1}{3}\right)\left(4x^2y^2-\dfrac{2xy}{3}+\dfrac{1}{9}\right)\)

f) \(125y^3-x^6\)

\(=\left(5y\right)^3-\left(x^2\right)^3\)

\(=\left(5y-x^2\right)\left(25y^2+5x^2y+x^4\right)\)