Question

Phân tích thành nhân tử 

a) 4x mũ 2 -  y mũ 2 + 4x +1

b) x mũ 3 - x + y mũ 3 - y

Answer 1

a ) \(4x^2-y^2+4x+1\)

= \(\left(4x^2+4x+1\right)-y^2=\left(2x+1\right)^2-y^2=\left(2x+1+y\right).\left(2x+1-y\right)\)

b ) \(x^3-x+y^3-y\)

= \(\left(x^3+y^3\right)-\left(x+y\right)\)

= \(\left(x+y\right)\left(x^2-xy+y^2\right)-\left(x+y\right)\)

= \(\left(x+y\right)\left(x^2-xy+y^2-1\right)\)

Chúc bạn học tốt !!!

Answer 2

\(a.\)\(4x^2-y^2+4x+1\)

\(=\left(4x^2+4x+1\right)-y^2\)

\(=\left(2x+1\right)^2-y^2\)

\(=\left(2x+1+y\right)\left(2x+1-y\right)\)

Answer 3

\(b.\)\(x^3-x+y^3-y\)

\(=\left(x^3+y^3\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(x^2-xy+y^2\right)\)

\(=\left(x+y\right)\left(x^2-xy+y^2-1\right)\)