Question

phan tich da thuc

7x^2+14xy

3x+12-(x^2+4x)

 

Answer 1

7x²+14xy=7x(x+2y)

3x+12-(x²+4x)=(3x+12)-(x²+4x)=3(x+4)-x(x+4)=(x+4)(3-x)

Answer 2

\(7x^2+14xy=7x\left(x+2y\right)\)

\(3x+12-\left(x^2+4x\right)=\left(-x+3\right)\left(x+4\right)\)