\(x^3-3x^2+4x-2=x^3-x^2-2x^2+2x-2=x^2\left(x-1\right)-2x\left(x-1\right)+2\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2-2x+2\right)\)
x3 - 3x2 + 4x - 2
= x3 - x2 - 2x2 + 2x + 2x - 2
= x2( x -1 ) - 2x( x - 1 ) + 2( x - 1 )
= ( x - 1 )( x2 - 2x + 2 )