Question

Phân tích đa thức thành nhân tử

ax² - ax + bx²  -bx + a + b

Answer 1

ax² - ax + bx²  -bx + a + b

= (ax²+ bx² ) - (ax + bx) + (a + b)

=x² (a + b) - x(a + b) + (a + b)

= (x² - x + 1)(a + b)

Answer 2

ax² - ax + bx² - bx + a + b

= ( ax² + bx² ) - ( ax + bx ) + ( a + b )

= x²( a + b ) - x( a + b ) + ( a + b )

= ( a + b )( x² - x + 1 )

Answer 3

\(ax^2-ax+bx^2-bx+a+b\)

\(=ax\left(x-1\right)+bx\left(x-1\right)+\left(a+b\right)\)

\(=x\left(x-1\right)\left(a+b\right)+\left(a+b\right)\)

\(=\left(a+b\right)\left(x^2-x+1\right)\)

Answer 4

\(ax^2-ax+bx^2-bx+a+b\)

\(=a.\left(x^2-x+1\right)+b.\left(x^2-x+1\right)\)

\(=\left(a+b\right)\left(x^2-x+1\right)\)