Question

Phân tích đa thức thành nhân tử:

1,3x³y + 6x²y² + 3 xy³

2,14x²y - 21xy² + 28x²y² 

3,x² (x-1) + 4(1-x)

4,10x(x-y) - 8(y-x)

5,8a(b-c) + 6b (c-b)

6,x² (x-1) + 16(1-x)

7,x² - xy + 5x - 5y

8,(3x + 1)² - (x + 1)² 

9,8x³ - 27y³

10,x² - 2x + 1 - 4y² 

 

Answer 1

\(1,=3xy\left(x^2+2xy+y^2\right)=3xy\left(x+y\right)^2\\ 2,=7xy\left(2x-3y+4xy\right)\\ 3,=\left(x-1\right)\left(x^2-4\right)=\left(x-2\right)\left(x+2\right)\left(x-1\right)\\ 4,=\left(x-y\right)\left(10x+8\right)=2\left(5x+4\right)\left(x-y\right)\\ 5,=\left(b-c\right)\left(8a-6b\right)=2\left(4a-3b\right)\left(b-c\right)\\ 6,=\left(x-1\right)\left(x^2-16\right)=\left(x-4\right)\left(x+4\right)\left(x-1\right)\\ 7,=x\left(x-y\right)+5\left(x-y\right)=\left(x-y\right)\left(x+5\right)\\ 8,=\left(3x+1-x-1\right)\left(3x+1+x+1\right)=2x\left(4x+2\right)=4x\left(2x+1\right)\\ 9,=\left(2x-3y\right)\left(4x^2+6xy+9y^2\right)\\ 10,=\left(x-1\right)^2-4y^2=\left(x-2y-1\right)\left(x+2y-1\right)\)