https://h7.net/hoi-dap/toan-8/phan-h-da-thuc-x-4-16-thanh-nhan-tu-faq324398.html
\(x^4+16x-12\)
\(=x^4+2x^3-2x^2-2x^3-4x^2+4x+6x^2+12x-12\)
\(=x^2.\left(x^2+2x-2\right)-2x.\left(x^2+2x-2\right)+6.\left(x^2+2x-2\right)\)
\(=\left(x^2+2x-2\right)\left(x^2-2x+6\right)\)
Làm
x4 + 16x - 12
= x4 + 2x3 - 2x2 - 2x3 - 4x2 + 4x + 6x 2 + 12x - 12
= x2 ( x2 + 2x - 2 ) - 2x ( x2 + 2x - 2 ) + 6( x2 + 2x - 2 )
=( x2 + 2x - 2 )( x2 - 2x + 6 )
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