Question

Phân tích đa thức thành nhân tử: x^2-x-2001.2002

Answer 1

`x^2-x-2001.2002`

`=x^2-2002x+2001x-2001.2002`

`=x(x-2002)+2001(x-2002)`

`=(x-2002)(x+2001)`.

Answer 2

x² - x - 2001.2002

= (x² - 2002x) + (2001x - 2001.2002)

= x(x - 2002) + 2001(x - 2002)

= (x + 2001)(x- 2002)

Answer 3

x²-x-2001.2002

=x²-x-2001(2001+1)

=x²-x-2001²-2001

=(x²-2001²)-(x+2001)

=(x-2001)(x+2001)-(x+2001)

=(x+2001)(x-2001-1)

=(x+2001)(x-2002)