( x-2 ) ^3 + 4^3
= hằng đẳng thức thứ 6 nha pạn
\(\left(x-2\right)^3+64\)
\(=\left(x-2\right)^3+4^3\)
\(=\left(x-2+4\right)\left[\left(x-2\right)^2-4\left(x-2\right)+4^2\right]\)
\(=\left(x+2\right)\left(x^2-4x+4-4x+8+16\right)\)
\(=\left(x+2\right)\left(x^2-8x+28\right)\)
Tham khảo nhé~
(x-2)3 + 64
= (x-2)3 + 43
= (x-2+4).[(x-2)2 - (x-2).4 + 42]
= (x+2).[x2 - 4x + 4 - 4x + 8 + 16]
= ( x+2).(x2 - 8x + 28)